#213379. [GCJ 2014 Finals] Symmetric Trees

Given a vertex-colored tree with nodes, can it be drawn in a 2D plane with a line of symmetry?

Formally, a tree is line-symmetric if each vertex can be assigned a location in the 2D plane such that:

• All locations are distinct.
• If vertex has color and coordinates , there must also be a vertex of color located at -- Note if is 0, and are the same vertex.
• For each edge , there must also exist an edge .
• If edges were represented by straight lines between their end vertices, no two edges would share any points except where adjacent edges touch at their endpoints.

The first line of the input gives the number of test cases, . test cases follow.

Each test case starts with a line containing a single integer , the number of vertices in the tree.

lines then follow, each containing a single uppercase letter. The -th line represents the color of the -th node.

lines then follow, each line containing two integers and . This denotes that the tree has an edge from the -th vertex to the -th vertex. The edges will describe a connected tree.

For each test case, output one line containing "Case #x: y", where is the case number (starting from 1) and is "SYMMETRIC" if the tree is line-symmetric by the definition above or "NOT SYMMETRIC" if it isn't.

样例输入 1

3
4
R
G
B
B
1 2
2 3
2 4
4
R
G
B
Y
1 2
2 3
2 4
12
Y
B
Y
G
R
G
Y
Y
B
B
B
R
1 3
1 9
1 10
2 3
3 7
3 8
3 11
4 8
5 7
6 7
8 12

样例输出 1

Case #1: SYMMETRIC
Case #2: NOT SYMMETRIC
Case #3: SYMMETRIC

Sample Explanation

The first case can be drawn as follows:

No arrangement of the second case has a line of symmetry:

One way of drawing the third case with a symmetry line is as follows:

Limits

Small dataset(7 Pts)

• Time Limit: 60 3 seconds

Large dataset(18 Pts)

• Time Limit: 120 5 seconds